The product of four consecutive positive integers
The product of four consecutive positive integers plus one is a square number
n(n + 1)(n + 2)(n + 3) + 1 = x2 where x is an integer.
Examples
1 × 2 × 3 × 4 + 1 = 52
2 × 3 × 4 × 5 + 1 = 112
3 × 4 × 5 × 6 + 1 = 192
4 × 5 × 6 × 7 + 1 = 292
5 × 6 × 7 × 8 + 1 = 412
6 × 7 × 8 × 9 + 1 = 552
7 × 8 × 9 × 10 + 1 = 712
8 × 9 × 10 × 11 + 1 = 892
9 × 10 × 11 × 12 + 1 = 1092
10 × 11 × 12 × 13 + 1 = 1312
Proof
n(n + 1)(n + 2)(n + 3) + 1 = n4 + 6n3 + 11n2 + 6n + 1
= (n2 + 3n + 1)2